# Statistical example the possibility example

Paper type: Mathematics,

Case Formulation, Applied Procedures, Food Labeling, Hospitality Supervision

#### Excerpt from Case Study:

The several possible items which could become the optimal answer are marked from one to four. The solutions to these are generally then given in Table you, along with the revenue which might result from these types of combinations. The values of each of these factors were worked out by resolving the coexisting equations the place that the lines crossed. It can be seen from Stand 1 the maximum revenue would be come to by generating 20 gound beef dinners and 40 fish dinners everyday.

Figure one particular: Feasible region for the linear coding problem

Table 1: Resulting profits via each of the crucial points

Stage

Value of X1

Value of X2

Resultant Profit

Now Exceed may also be used to solve this problem. The solution which is presented is demonstrated in Physique 2 . From this it may be confirmed that the maximum solution for the cafe is to prepare 20 beef meals and 40 seafood meals each night. The tenderness report is usually given in this model in Figure several.

Figure two: Computer Strategy to the Linear Programming Issue

Figure several: Sensitivity Output from the Excel Model

Additionally it is possible that these types of solutions may be used to answer further more questions relevant to the problems. For instance , if the cash in on the seafood dinners grew up to be comparable to the profit in the beef meals this would after that change the ideal solution to one out of which any kind of point at risk between points 3 and 4 would produce similar profit. The money overall will also be improved subject to this kind of increase in value not impacting the number of customers overall. Likewise, if it was determined that at least 20% of customers would want gound beef dinners, this kind of also would not change the optimum meal preparing, as this will move one of the lines, will but not alter which from the points offered the optimal answer, where much more than 20% happen to be beef dinners anyway.

It is additionally possible to resolve the problems provided in the second case study in the model shown. It would certainly not be worth them paying for an advertisement to increase the total number of dishes. This is because it can be seen from Figure 1 and Physique 2 which the labor constraint is capturing at the present time. Because of this they would not have the labor available to enhance their meal output in a way which will would generate more earnings.

Also, as the labor is a binding factor within the current optimal solution to the programming difficulty, this means that a decrease in labor would decrease the profit obtainable. In fact , this will change the parameters of the optimum solution to 12 beef dishes and 40 fish dinners, with simply \$640 earnings rather than \$800. Finally, in case the profit from the fish meals was going to be changed, then the actual solution to the situation would not modify, all that happens is that the earnings would be raised to \$880. Therefore , Calcul should have no difficulties with this!

Conclusions and Recommendations

It may be viewed from the alternatives presented furthermore the best technique for the cafe based on this may be to produce 20 beef meals and 45 fish meals at the present time. From the sensitivity analysis it would however seem the number of food which was produced could be reduced by two without modifying the optimal remedy, so it would possibly benefit all of them under it to rather produce only 58 dishes. Then in the event that there was a larger demand it would serve these people well to re-assess the whole model. By way of example if they will found that they can had a increased demand for foods then they could in fact need to add to the labor hours prior to they would manage to increase their profitability.

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